NTA UGC NET 25 June 2025 Second Shift Reasoning Questions with Answers (Paper 1)

🔢 NTA UGC NET, 25 June 2025, Second Shift, Reasoning

Question 01

Solution of A

✅ So, A → III (3)

🧠 Question 02:

Given:
"WHERE" → 5, 18, 5, 8, 23
"DELHI" → 9, 8, 12, 5, 4

🔍 Step 1: Reverse the word

"WHERE" reversed = "EREHW" → E(5), R(18), E(5), H(8), W(23) ✅
"DELHI" reversed = "IHLED" → I(9), H(8), L(12), E(5), D(4) ✅

So the pattern is:
➤ Reverse the word → Write position of each letter in the alphabet

✍️ Step 2: Apply to "HORSE"

Reversed "HORSE" → "ESROH"

Letter	Position in Alphabet
E	5
S	19
R	18
O	15
H	8

✅ Final Answer: Option 2 — 5, 19, 18, 15, 8

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🔢 Question 03: Number Series

Given Series: 3, 8, 15, 24, 35, 48, ?

🔍 Step-by-step differences:

• 8 − 3 = 5
• 15 − 8 = 7
• 24 − 15 = 9
• 35 − 24 = 11
• 48 − 35 = 13

Pattern of differences: 5, 7, 9, 11, 13 → Consecutive odd numbers

Next difference = 15
Next number = 48 + 15 = 63

✅ Final Answer: Option 3 — 63

🔢 Question 04: Compound Interest

🔢 Question 05: Match the LIST-I with LIST-II

सूचि-I को सूचि-II से मिलाएं

LIST-I (प्रश्न)	LIST-II (उत्तर)
A. If, x + 1/x = 2, then (x - 1/x) = ?	I. 11
B. If, x − y = 1 and x² + y² = 41, then x + y = ?	II. 2
C. If (1 − 1/x) = 2, then 1 + 1/x² = ?	III. 0
D. If (x − 1/x) = 3, then x² + 1/x² = ?	IV. ±9

✅ Solution (हल):

A. Given: x + 1/x = 2
Use identity: (x + 1/x)² = x² + 1/x² + 2 ⇒ 4 = x² + 1/x² + 2 ⇒ x² + 1/x² = 2
Now, (x - 1/x)² = x² + 1/x² - 2 = 2 - 2 = 0 ⇒ x - 1/x = 0
✅ So, A → III (0)

B. Given: x - y = 1 and x² + y² = 41
Use identity: (x − y)² = x² + y² − 2xy ⇒ 1 = 41 − 2xy ⇒ 2xy = 40 ⇒ xy = 20
Now, (x + y)² = x² + y² + 2xy = 41 + 40 = 81 ⇒ x + y = ±9
✅ So, B → IV (±9)

C. Given: 1 − 1/x = 2 ⇒ 1/x = −1
Then: 1 + 1/x² = 1 + (−1)² = 1 + 1 = 2
✅ So, C → II (2)

D. Given: x − 1/x = 3
Use identity: (x − 1/x)² = x² + 1/x² − 2 ⇒ 9 = x² + 1/x² − 2 ⇒ x² + 1/x² = 11
✅ So, D → I (11)

✅ Final Matching (अंतिम मिलान):

प्रश्न	उत्तर
A	III (0)
B	IV (±9)
C	II (2)
D	I (11)

✔ Correct Option: Option 4️⃣ (A-III, B-IV, C-II, D-I)